(x^2+x+1)*(x^2+x+1)=12

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Solution for (x^2+x+1)*(x^2+x+1)=12 equation:


Simplifying
(x2 + x + 1)(x2 + x + 1) = 12

Reorder the terms:
(1 + x + x2)(x2 + x + 1) = 12

Reorder the terms:
(1 + x + x2)(1 + x + x2) = 12

Multiply (1 + x + x2) * (1 + x + x2)
(1(1 + x + x2) + x(1 + x + x2) + x2(1 + x + x2)) = 12
((1 * 1 + x * 1 + x2 * 1) + x(1 + x + x2) + x2(1 + x + x2)) = 12
((1 + 1x + 1x2) + x(1 + x + x2) + x2(1 + x + x2)) = 12
(1 + 1x + 1x2 + (1 * x + x * x + x2 * x) + x2(1 + x + x2)) = 12
(1 + 1x + 1x2 + (1x + x2 + x3) + x2(1 + x + x2)) = 12
(1 + 1x + 1x2 + 1x + x2 + x3 + (1 * x2 + x * x2 + x2 * x2)) = 12
(1 + 1x + 1x2 + 1x + x2 + x3 + (1x2 + x3 + x4)) = 12

Reorder the terms:
(1 + 1x + 1x + 1x2 + x2 + 1x2 + x3 + x3 + x4) = 12

Combine like terms: 1x + 1x = 2x
(1 + 2x + 1x2 + x2 + 1x2 + x3 + x3 + x4) = 12

Combine like terms: 1x2 + x2 = 2x2
(1 + 2x + 2x2 + 1x2 + x3 + x3 + x4) = 12

Combine like terms: 2x2 + 1x2 = 3x2
(1 + 2x + 3x2 + x3 + x3 + x4) = 12

Combine like terms: x3 + x3 = 2x3
(1 + 2x + 3x2 + 2x3 + x4) = 12

Solving
1 + 2x + 3x2 + 2x3 + x4 = 12

Solving for variable 'x'.

Reorder the terms:
1 + -12 + 2x + 3x2 + 2x3 + x4 = 12 + -12

Combine like terms: 1 + -12 = -11
-11 + 2x + 3x2 + 2x3 + x4 = 12 + -12

Combine like terms: 12 + -12 = 0
-11 + 2x + 3x2 + 2x3 + x4 = 0

The solution to this equation could not be determined.

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